Ans : Increase

Explanation :- Let power and voltage of each bulb are P and V respectively.

Then, resistance of each bulb is R = V²/P

Case 1:- When all the bulbs are connected in series then, equivalent resistance of circuit is given by Req = R + R + R + ..... Upto 30 terms

Req = 30R = 30V²/P

current passing through each bulb is i₁ = E/Req = E/30V²/P = PE/30V² -----(1)

Here E is the potential difference of circuit.

Case2:- Now, a bulb is fused. And 29 bulbs are connected in circuit.

So, equivalent resistance of 29 bulbs in series combination,

Req = R + R + R + .... Upto 29 terms

Req ' = 29R = 29V²/P

Current passing each bulb is i₂ = E/29V²/P = PE/29V² -----(2/

What we observed ? From case 1 and case 2 i₂ > i₁

e.g., current flow through each bulb is higher than initial.

Means power out put = i²R will be higher

Hence, room's light increased.

3 Opinions

Ans : IncreaseExplanation :- Let power and voltage of each bulb are P and V respectively.

Then, resistance of each bulb is R = V²/P

Case 1:- When all the bulbs are connected in series then, equivalent resistance of circuit is given by Req = R + R + R + ..... Upto 30 terms

Req = 30R = 30V²/P

current passing through each bulb is i₁ = E/Req = E/30V²/P = PE/30V² -----(1)

Here E is the potential difference of circuit.

Case2:- Now, a bulb is fused. And 29 bulbs are connected in circuit.

So, equivalent resistance of 29 bulbs in series combination,

Req = R + R + R + .... Upto 29 terms

Req ' = 29R = 29V²/P

Current passing each bulb is i₂ = E/29V²/P = PE/29V² -----(2/

What we observed ? From case 1 and case 2 i₂ > i₁

e.g., current flow through each bulb is higher than initial.

Means power out put = i²R will be higher

Hence, room's light increased.